8[x+1]=2[x+16]

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Solution for 8[x+1]=2[x+16] equation:


Simplifying
8[x + 1] = 2[x + 16]

Reorder the terms:
8[1 + x] = 2[x + 16]
[1 * 8 + x * 8] = 2[x + 16]
[8 + 8x] = 2[x + 16]

Reorder the terms:
8 + 8x = 2[16 + x]
8 + 8x = [16 * 2 + x * 2]
8 + 8x = [32 + 2x]

Solving
8 + 8x = 32 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
8 + 8x + -2x = 32 + 2x + -2x

Combine like terms: 8x + -2x = 6x
8 + 6x = 32 + 2x + -2x

Combine like terms: 2x + -2x = 0
8 + 6x = 32 + 0
8 + 6x = 32

Add '-8' to each side of the equation.
8 + -8 + 6x = 32 + -8

Combine like terms: 8 + -8 = 0
0 + 6x = 32 + -8
6x = 32 + -8

Combine like terms: 32 + -8 = 24
6x = 24

Divide each side by '6'.
x = 4

Simplifying
x = 4

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